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0.75t^2-27=0
a = 0.75; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·0.75·(-27)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-9}{2*0.75}=\frac{-9}{1.5} =-6 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+9}{2*0.75}=\frac{9}{1.5} =6 $
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